The Isoperimetric Inequality #
This file formalises basic properties of classical Fourier series needed on the way to the isoperimetric inequality. In particular we prove:
- Parseval's theorem –
Parsevals_thm - Wirtinger's inequality –
Wirtingers_inequality
Main results #
Parseval's theorem (Parsevals_thm) #
Given a Fourier series f(x) = a₀/2 + ∑_{n≥1} (aₙ cos(nx) + bₙ sin(nx)),
under suitable integrability and summability hypotheses,
(1/π) ∫_{-π}^{π} f(x)² dx = (1/2) a₀² + ∑_{n≥1} (aₙ² + bₙ²).
Wirtinger's inequality (Wirtingers_inequality) #
Given the same Fourier series, the Parseval identity applied to the derivative series yields
(1/π) ∫_{-π}^{π} (f'(x))² dx = ∑_{n≥1} n² (aₙ² + bₙ²).
This is the continuous analogue of the discrete Wirtinger inequality, and reflects that
differentiation weights each Fourier mode by its frequency n.
Notation #
Throughout, a : ℕ → ℝ and b : ℕ → ℝ are the cosine and sine Fourier coefficients,
and the series is indexed over ℕ+ (positive natural numbers).
The N-th partial sum of the Fourier series:
S_N(x) = a₀/2 + ∑_{n=1}^N (aₙ cos(nx) + bₙ sin(nx)).
Equations
Instances For
The Fourier series decomposes as f(x) = a₀/2 + S(x),
where S(x) is the oscillatory sum part.
Expansion of (f(x))² as (a₀/2)² + a₀·S(x) + S(x)²,
where S(x) = fourierSum a b x.
Expands the square of the sine partial sum into a double sum:
(∑ bₙ sin(nx))² = ∑ₙ ∑ₘ bₙ bₘ sin(nx) sin(mx).
Expands the square of the cosine partial sum into a double sum:
(∑ aₙ cos(nx))² = ∑ₙ ∑ₘ aₙ aₘ cos(nx) cos(mx).
Full expansion of (f(x))² into a constant term, cross terms, and double sums,
combining fourierSeries_sq, expand_square, expand_cos_sq, and expand_sin_sq.
The cross term integrates to zero over [-π, π]:
∫_{-π}^{π} a₀ · (∑_{n≥1} aₙ cos(nx) + bₙ sin(nx)) dx = 0.
Parseval's theorem: Given square-integrability and suitable summability hypotheses,
(1/π) ∫_{-π}^{π} f(x)² dx = (1/2) a₀² + ∑_{n≥1} (aₙ² + bₙ²).
Weierstrass M-test for Fourier series: If ∑ (‖aₙ‖ + ‖bₙ‖) converges, then the
Fourier partial sums converge uniformly to fourierSeries a b on all of ℝ.
If ∑ (‖aₙ‖ + ‖bₙ‖) converges, then the Fourier series fourierSeries a b is
continuous on all of ℝ.
If ∑ n * (‖aₙ‖ + ‖bₙ‖) converges, the partial sums of the derivative series converge
uniformly to fourierDeriv a b (Weierstrass M-test applied to the derivative).
Each Fourier term is differentiable:
d/dx [aₙ cos(nx) + bₙ sin(nx)] = -n aₙ sin(nx) + n bₙ cos(nx).
The N-th partial sum is differentiable, with derivative equal to the partial sum of
term-wise derivatives.
Term-by-term differentiation: HasDerivAt (fourierSeries a b) (fourierDeriv a b x) x
whenever ∑ n * (‖aₙ‖ + ‖bₙ‖) and ∑ (‖aₙ‖ + ‖bₙ‖) both converge.
If ∑ n * (‖aₙ‖ + ‖bₙ‖) and ∑ (‖aₙ‖ + ‖bₙ‖) both converge, then the Fourier series
fourierSeries a b is differentiable on all of ℝ, with derivative fourierDeriv a b.
Wirtinger's inequality: (1/pi) * int (f'(x))^2 = sum n^2 * (a n^2 + b n^2).
The integral formula h_int_sq is the Parseval identity for the derivative series,
mirroring the h_int_sq hypothesis in Parsevals_thm.